数据库实战：【获取部门当前经理的薪水情况】

题目描述

获取所有部门当前(dept_manager.to_date='9999-01-01')manager的当前(salaries.to_date='9999-01-01')薪水情况，给出dept_no, emp_no以及salary(请注意，同一个人可能有多条薪水情况记录)

CREATE TABLE `dept_manager` (
`dept_no` char(4) NOT NULL,
`emp_no` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`dept_no`));
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));

答案

select d.dept_no,d.emp_no,s.salary from dept_manager as d inner join salaries as s on d.emp_no = s.emp_no where d.to_date='9999-01-01' and s.to_date = d.to_date